A number when divided successively by 6, 7 and 8 leave the respective remainders 35 and 4 what will be the last remainder when so that least possible number is divided successively 876
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Hi ...dear.
here is your answer....
number which divided by 8 will be quotient from division by 7 = 8x + 4
number which divided by 7 will be quotient from division by 5 = 7(8x+4) + 3 = 56x +31
The original number which we divided by 5 =5(56x +31) + 2
= 280x +155 +2
= 280x + 157
When this number is divided by 8 = ( 280x+ 157)/8 = 35x + 19 and a remainder of 5
On dividing by 7 , ( 35x + 19) / 7 = 5x + 2 and a remainder of 5
On Dividing by 5 , (5x+2)/5 = x and a remainder of 2
Hence the remainders will be 5,5 and 2.....
hope it helped you
Brainly Star Community
#shubhendu
here is your answer....
number which divided by 8 will be quotient from division by 7 = 8x + 4
number which divided by 7 will be quotient from division by 5 = 7(8x+4) + 3 = 56x +31
The original number which we divided by 5 =5(56x +31) + 2
= 280x +155 +2
= 280x + 157
When this number is divided by 8 = ( 280x+ 157)/8 = 35x + 19 and a remainder of 5
On dividing by 7 , ( 35x + 19) / 7 = 5x + 2 and a remainder of 5
On Dividing by 5 , (5x+2)/5 = x and a remainder of 2
Hence the remainders will be 5,5 and 2.....
hope it helped you
Brainly Star Community
#shubhendu
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