Question

A number when multiplied by 0, exceeds itself by 81. Find the number. ​

Answer 1

Answer:

Let the number be x,

ATQ

4x = x+45

4x-x = 45 (transposing)

3x = 45

x = 45/3

x = 15

CHECKING -

4x = x+45

(4×15) = (15+45)

60 = 60

LHS=RHS

Checked.