Question

a number when multiplied by 3 exceeds itself by 40 find the number​

Answer 1

Answer:

Let the number be X

X when multiplied by 3 = 3X

Now

A/Q

WHEN THE NUMBER MULTIPIED BY 3 ITSELF EXCEED BY 40

$= > 3x - x = 40$

$= > 2x = 40$

$= > x = 40 \div 2$

$= > x = 20$

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