Question

A number when multiplied by 3,exceeds itself by 40.find the number

Answer 1

Answer:

Let the number be x

When x is multiplied by 3 = 3x exceed by 40

$= > 3x = 40 + x$

$= > 3x - x = 40$

$= > 2x = 40$

$= > x = 40 \div 2$

$= > x = 20$

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Answer 2

Answer:

The number is 20

Step-by-step explanation:

Let x be the number

A number is multiplied by 3

So, Number becomes 3x

A number when multiplied by 3,exceeds itself by 40

$3x-x=40$

$2x=40$

$x=\frac{40}{2}$

$x=20$

Hence the number is 20