Question

A number when multiplied by 5 is 20 more then itself.

Answer 1

The number is 5

Given:

A number when multiplied by 5 is 20 more than itself.

To find:

The number which is 20 more than itself when multiplied by 5

Solution:

Let x be the required number

Given that when x is multiplied by 5 the resultant number 5x is 20 more than x

as we know the number which is 20 to x = x+20

Now convert the above line into a mathematical expression

⇒ 5x = x + 20  now simplify it to get x value

⇒ 5x - x = 20

⇒ 4x = 20

⇒ x = 5

Therefore, the required number is 5

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Answer 2

Answer: number is 5

Step-by-step explanation:

Given: a number when multiplied by 5 is 20 more than itself

To find: number?

Solution: Let the unknown number be x

If x is that number which is when multiplied by 5 is 20 more than itself then it must satisfy the following equation:

$5x=20+x$..............(1)

This expression clearly states the fact that x is the number that is multiplying by the constant 5 and is equal to 20 more than the number that is x itself.

On solving equation (1) we get ,

$4x=20$

on further solving we get the value of x as,

$x=5$

Hence x=5 is the number which is when multiplied by 5 is 20 more than itself

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