Question

A number when multiplied by 8, exceeds itself by 35. Find the number.

Answer 1

Given : A number when multiplied by 8, exceeds itself by 35.

Exigency to find : The number .

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❍ Let's Consider the number be x .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\: \: According \:\:\:To\: \:\:\: the\:\: \: Given \:\:\: Question \::}}$

━━━━ A number when multiplied by 8, exceeds itself by 35 .

$\qquad:\implies \sf 8\times x = x + 35$

$\qquad:\implies \sf 8x = x + 35$

$\qquad:\implies \sf 8 x - x = 35$

$\qquad:\implies \sf 7x = 35$

$\qquad:\implies \sf x = \dfrac{35}{7}$

$\qquad:\implies \sf x = \cancel {\dfrac{35}{7}}$

$\qquad \longmapsto \frak{\underline{\purple{\:x = 5 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The \:required \:number \:is\:\bf{5}}}}$

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V E R I F I C A T I O N :

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\: \: According \:\:\:To\: \:\:\: the\:\: \: Given \:\:\: Question \::}}$

━━━━ A number when multiplied by 8, exceeds itself by 35 .

As , We know that ,

• The number is 5 .

$\qquad:\implies \sf 8\times 5 = 5 + 35$

$\qquad:\implies \sf 40 = 5 + 35$

$\qquad:\implies \bf 40 = 40$

⠀⠀⠀⠀⠀$\therefore {\underline {\bf{ Hence, \:Verified \:}}}$

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