A number when successively divided by 5,3,2 gives 0,2,1 as remainders.what will be the remainders when the same number is successively divided by 2,3,5
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we have 5,3,2 which gives remainder 0,2,1
subtract the remainder from the divisor
so (5-0) = 5
(3-2) = 1
(2-1) = 1
we have 5,1,1 and now we will take LCM = 5
so the number is 5 which when divided by 5,3,2 respectively will give remainders 0,2,1
now as the number is 5 then it has to be divided by 2,3,5 respectively which will give us remainders as 1,2,0
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