Question

a number when successively divided by 9, 11 and 13 leaves remainders 8, 9 and 8 respectively. solution

Answer 1

9   x

11   y   -8

13  z    -9

    1     -8

z = (13x1+8)= 21

y = (11z +9) = 11x21+9=130

x = (9y+8) = 9x130+8 = 1178

Number is 1178