Question

a number which when increased by 10% becomes 55 what is the number ​

Answer 1

Step-by-step explanation:

10%=1/10

Let the number=10x

Increased by=10x+x=11x

Here

11x=55(given)

x=55/11=5

So

Number=5×10=50

Answer 2

ANSWER:

Let the number be x.

So, ATQ :- x + (10/100 × x) = 55

=> (100x+10x)/100 = 55

=> 110x = 55×100 (Cross multiply)

=> x = 5500/110

=> x = 50

Therefore , required number is 55.

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