a number whose fifth part increased by 5 is equal to its fourth part diminished by 5 find the number
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Let the number be x.
5th part of the number = x/5
Fifth part of the number increased by 5
So The number is
= x/5 + 5
4th part of the number = x/4
4th part of the number diminished by 5 = x/4 - 5
⇒ x/5 + 5 = x/4 - 5
⇒ x/5 - x/4 = - 5 - 5
⇒ x/5 - x/4 = - 5 - 5
⇒ -x/20 = -10
⇒ x = 200
Therefore, the required number is 200.
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Thank you
Let the number be x.
5th part of the number = x/5
Fifth part of the number increased by 5
So The number is
= x/5 + 5
4th part of the number = x/4
4th part of the number diminished by 5 = x/4 - 5
⇒ x/5 + 5 = x/4 - 5
⇒ x/5 - x/4 = - 5 - 5
⇒ x/5 - x/4 = - 5 - 5
⇒ -x/20 = -10
⇒ x = 200
Therefore, the required number is 200.
HOPE IT HELPS YOU
Thank you
suraj12187:
i am in 8th
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