Question

a number whose one fifth part increased by 4 is equal to its one fourth part diminished by 10 find the number?​

Answer 1

The required number = 280

Given:

A number whose one fifth part increased by 4 is equal to its one fourth part diminished by 10

To find:

Find the above number

Solution:

Let x be the required number

Given One fifth part increased by 4 is equal to its one fourth part diminished by 10

One fifth part of x is increased by 4, then

mathematical expression will be = $\frac{1}{5} (x) + 4$ = $\frac{x}{5} + 4$  

One fourth part of x is diminished by 10, then

mathematical expression will be = $\frac{1}{4} (x) -10$ =  $\frac{x}{4} -10$

From given data,

⇒  $\frac{x}{5} + 4 =$ $\frac{x}{4} -10$  

⇒  $\frac{x+ 20}{5} =$ $\frac{x- 40}{4}$  

⇒ 4(x+20) = 5(x-40)

⇒ 4x + 80 = 5x - 200

⇒  5x - 4x =200 + 80

⇒  x = 280

The required number = 280

#SPJ2

Answer 2

Answer:

The answer to the given question is the required number is 280.

Step-by-step explanation:

Given:

The fifth part of the number is increased by 4 and is equal to one-fourth part that is diminished by 10.

To find :

we have to find the number.

Solution :

let the required number be y.

It is given that the fifth part of the number is increased by 4 = one-fourth part that is diminished by 10

The mathematical expression for the fifth part of the number is increased by 4 is

$\frac{1}{5} y + 4 = \frac{y}{5} + 4$

The mathematical expression for one-fourth part is diminished by 10.

$\frac{1}{4} y - 10 \\ \frac{y}{4} - 10$

Based on the data given in the question,

$\frac{y}{5} + 4 = \frac{y}{4} - 10$

on taking the LCM the value will be

$\frac{y + 20}{5} = \frac{y - 40}{4}$

On cross-multiplying, we get the value as

$4y + 80 = 5y - 200$

Taking the like terms on the same side,

$5y - 4y = 200 + 80 \\ y = 280$

The value of the number required is 280.

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