Math, asked by mdmahtab79911, 4 months ago

a number whose seventh part exceeds it's eight part by 2, is
(i) 64 (ii) 56
(iii) 58 (iv) 68
solve with full solution and write which option is right​

Answers

Answered by tennetiraj86
2

Answer:

There is no correct option

the correct answer is 112

Step-by-step explanation:

Given:-

a number whose seventh part exceeds it's eight part by 2.

To find:-

Find the number.

Solution:-

Let the number be X

Seventh part of the number=X/7

Eighth part of the number=X/8

Given that

The number whose seventh part exceeds it's eight part by 2

=>(X/7)-(X/8)=2

LCM of 7 and 8 =56

=>(8X-7X)/56=2

=>X/56=2

=>X=56×2

=>X=112

Answer:-

The number=112

Check:-

The number=112

Seventh part of 112=112/7=16

Eighth part of 112=112/8=14

Their difference=16-14=2

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