Question

A number whose square root is twice of its cube root is

Answer 1

Answer:

Step-by-step explanation:

Let the number be x

A/q

(x^1/2) = 2 * (x^1/3)

Squaring both sides

(x^1/2)^2 = [2 * (x^1/3)]^2

(x)^(1/2*2) = 2^2 * (x)^(1/3 * 2)

x = 4 * x^2/3

Cubing both sides

x^3 =[4 * x^2/3]^3

x^3 = 4^3 * x^(3*2/3)

x^3 = 64 * x^2

x^3 - 64x^2 = 0

x^2 [ x - 64 ] = 0

x = 0 or 64

Your answer is 0 and 64

cube root of 64 = 4

square root of 64 = 8

4*2=8

for 0 both are 0

0*2=0

Hope it helps :-)

Answer 2

Answer:

plzzz give me brainliest ans and plzzzz follow me