Question

A number x is 4 less than three times another number y. If their sum is increased by 5, the result is 25. Find both the numbers

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Answer 1

$\huge \underline \mathbb {SOLUTION:-}$

AnsWer:

• First number is 6.
• Second number is 14.

Given:

• A number x is 4 less than three times another number y. If their sum is increased by 5, the result is 25.

Need To Find:

• Find the first and second number

Explanation:

Let the first number be x.

Let the second number be y.

According to given condition:

• y = 3x -4

Also given that:

• If sum is increased by 5 then result is 25

So the equation can be written as

• x + y + 5 = 25

Substituting the value of y we get:

x + 3x - 5 + 5 = 25

➠ 4x + 1 = 25

➠ 4x = 24

➠ x = 6

Hence:

• First number is 6.
• Second Number = y = 3 (6) -4 = 14

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Answer 2

✬ First Number = 6 ✬

✬ Second Number = 14 ✬

Step-by-step explanation:

Given:

• A number x is 4 less than three times another number y.
• After increasing their sum by 5 the result is 25.

To Find:

• What are the two numbers?

Solution: Let the second number be x and first number be y

A/q

• x = 4 less than 3 times of y
• → x = 3y – 4.........(1)

$\small\implies{\sf }$ x + y + 5 = 25

$\small\implies{\sf }$ 3y – 4 + y + 5 = 25 [ From equation 1 ]

$\small\implies{\sf }$ 4y + 1 = 25

$\small\implies{\sf }$ 4y = 25 – 1

$\small\implies{\sf }$ 4y = 24

$\small\implies{\sf }$ y = 24 / 4

$\small\implies{\sf }$ y = 6

• Put the value of y in equation 1 •

→ x = 3y – 4

→ x = 3(6) – 4

→ x = 18 – 4

→ x = 14

Hence, First number is y = 6 and second number x = 14