Question

A number x is randomly selected from the numbers
1, 2 and 3, then a second number y is randomly
selected from the numbers 1, 4 and 9. What is the
probability that the product xy of the two numbers
will be less than 9?

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Answer 1

${\huge{\underline{\underline{\rm{SolutiOn:}}}}}$

${\bf{\pink{Given\:that:-}}}$

Total number of elementary events are

= 3×3 = 9

${\huge{\boxed{\tt{\red{Concept\:Used:}}}}}$

$\bf \boxed{Probability = \frac{No. \: of \: favourable \:outcomes }{Total \: possible \: outcomes} }$

${\huge{-:EXPLANATION:-}}$

Let E be the event of (xy<9)

${\bf{\blue{\underline{Favourable\:outcomes\:are:}}}}$

1×1=1, 1×4=4, 2×1=2, 2×4=8, 3×1=3

So, the number of favourable outcomes are = 5

Hence,

$\huge \green{P(xy < 9) = \frac{5}{9} }$

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