Math, asked by 2018233hridesh, 4 months ago

A number y,when added to it's double gives 48.Form a linear equation and find the number

Answers

Answered by Anonymous10102005
1

y + 2y = 48

3y = 48

y = 48/3

y = 16

Answered by TwilightShine
3

Question -:

A number y, when added to its double gives 48. Form a linear equation and find the number.

\blue\star Answer -:

Let the number be y.

Its double = 2y.

Adding y in it, we get 2y + y.

The result is 48.

So, the equation =

2y + y = 48

3y = 48

y =  \frac{48}{3}

y = 16

Thus, the required number is 16.

Verification -:

Since in the question it was mentioned that the required number, when added to its double, will give 48, therefore, to check whether your answer is right or not, just add the required number to its double and see if you get 48.

The required number y = 16.

Its double 2y = 16 × 2 = 32.

Now, the sum of the required number and its double = 16 + 32 = 48.

Since we got 48,

Hence verified

Hope it helps! :)

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