Question

a numbers of identical cells n each of emf E , internal resistance r connected in series are charged by a DC source of emf E' using resistor R
a) draw the circuit
b) deduce the expression for the charging current and potential difference across the combination of cells.
pls answer fast
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Answer 1

Explanation:

The circuit arrangement is shown in figure.

Applying Kirchhoff;s second law to the circuit abcda

nε−l(nr)−lR+ε

′

=0

⇒

a) Charing current , I=

R+nr

ε−nε

b) Potential difference across the combination V is given by

V−IR+ε

′

=0

⇒V=ε

′

−IR⇒V=ε

′

R+nr

(ε

′

−ne)

⇒V=

R+nr

ε

′

(R+nr)−ε

′

+nε

⇒V=

R+nr

ε

′

(R+nr−1)+nε

Answer 2

Answer:

I don't want to answer this question