A numbrr which leaves remainder 1 when devided by 9 8 7 and 6 but completely divisible by 5
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Answer:
505
Step-by-step explanation:
It leaves a remainder 1 when divided by 9, 8, 7 and 6
=> it leaves a remainder 1 when divided by the LCM of 9, 8, 7 and 6
=> it leaves a remainder 1 when divided by 9×8×7 = 504
The first number that we consider works right away....
505 is one more than 504, so leaves a remainder of 1 when divided by 9, 8, 7 and 6, and it is obviously divisible by 5.
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