Question

A numbrr which leaves remainder 1 when devided by 9 8 7 and 6 but completely divisible by 5

Answer 1

Answer:

505

Step-by-step explanation:

It leaves a remainder 1 when divided by 9, 8, 7 and 6

=> it leaves a remainder 1 when divided by the LCM of 9, 8, 7 and 6

=> it leaves a remainder 1 when divided by 9×8×7 = 504

The first number that we consider works right away....

505 is one more than 504, so leaves a remainder of 1 when divided by 9, 8, 7 and 6, and it is obviously divisible by 5.