Math, asked by akhizar2, 10 months ago

a numeric lock has a 3 digit key 682 one num is correct and well placed, 614 one num is correct but wrongly placed, 206 two num are correct but wrongly placed, 738 nothing is correct, 780 one num is correct but wrongly placed, what is 3 digit code ​

Answers

Answered by swan030782
7

Answer:

Hint 1 : (6,8,2) one number is correct & well placed.

Hint 2 : (6,1,4) one number is correct but wrong placed.

Hint 3 : (2,0,6) Two number are correct but wrong placed.

Hint 4: (7,3,8) Nothing is correct.

Hint 5 : (7,8,0) one number is correct but wrong placed.

From Hint 1 & 2 , we come to know that the number 6 is incorrect number.

From Hint 3 , we come to know that 2 & 0 are correct numbers.

From Hint 4 & 1 , we come to know that number 2 is correctly placed.

Hence the number will be _ _ 2

From Hint 3, 4 & 5 we come to know that 0 is wrongly placed in (2,06) & (7,8,0) .

Hence the number will be

(0 _ 2)

And from Hint 2 we come to know that the middle number is 4

====================

Therefore the 3-digit number is ;

0 4 2

Answered by poojan
1

Therefore, the co-de of the given numerical lock is 042.

Decoding the clues given:

On observing the rules given, from the fourth rule, we get that the lock contains no numbers from the list [7, 3, 8]. So, from the first rule 6, 2 remains.

From the second rule, we get that one number among 6, 1, 4 is correct but wrongly placed. But the number 6 is in the same position in rules 1 and 2. So, there is no chance of 6 being among the three numbers of the lock.

So, from the first rule, we get that the number at the last position is 2 as it says that the number is well placed.

_ _ 2

In the third rule, if we eliminate 6, the remaining numbers are 2, 0. They are correct but wrongly placed. As 2 is fixed with the last position, 0 goes for the first position as per the rule.

0 _ 2

Now, from rule 2, we get that one number is correct among 1, 4 but is wrongly placed. If 1 is correct, it would be well placed and that contradicts the rule which says that the number is wrongly placed. So, the correct number that should be in the second position is 4

0 4 2

Therefore, the co-de of the given numerical lock is 042.

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