Question

A numerical lock can be opened using any possible combination of these five digits 0, 1, 0, 3 and 2 (example 20031). John used all possible incorrect combinations on the 5-digit lock before finally opening the lock at the next attempt. How many total attempts did he make? The digits available are 0-5 in lock ​

Answer 1

let’s see, for only one digit you have 4 combination, for two digit you have 16 combinations, for three you have 64 combinations, for four you have 256 combinations - wow they’re rising quickly!- for five you have an astounding 1024 combinations.

so for any combination, or numerical system ab= n° of combinations

where “a” is the number of combination of a single digit “lock” while “b” is the number of digits!

#hopeitshelpyou:)

Answer 2

i thik i am right and good night