Question

A nurse applies a force of 3.8 N to the syringe's piston of radius 0.9 cm. Find the increase in pressure of the fluid in the syringe?
(1) 14.927 kPa
(2) 469.13 Pa
(3) 46.9 mPa
(4) 422 Pa​

Answer 1

$\large\bold\orange{\underline{Answer:-}}$

➻ Increase in pressure of the fluid in the syringe (ΔP) = $\frac{Force \ applied}{Area \ of \ cross \ section \ of \ syringe}$

✯ Area of cross section = πr²

$\large\implies$ π × (0.9)² cm² = π × (0.9)² × [(-10) × (-10) × (-10) × (-10)]

Therefore,

ΔP = $\frac{3.8}{π(0.9 × 0.9) × [(-10) × (-10) × (-10) × (-10)]}$ = $\boxed{\bold{\purple{14.927 kPa}}}$

Answer 2

The answer is their in the above picture.

Hope it helps you.