A nurse applies a force of 4.40 N to the piston of a syringe. The piston has an area 5.00 × 10−5 m2.
What is the pressure increase in the fluid within the syringe?
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Answer:
* means power of
Explanation:
Increase in pressure of the fluid in the syringe (ΔP)
= Force applied /area of cross section of syringe
Area of cross section= πr*2
==π×(0.9) *2 cm *2
=π×(0.9) *2 ×10 *−4
∴ΔP= 3.8/π(0.9) *2 ×10 *−4
=14.927k Pa
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