Question

A nut can be opened by a lever of length 0.25 m
applying a force of 80N. What should be the leng
of lever, if a force of 32 N is enough to open t
nut?
Anyone please tell me the answer and I will mark you the brainliest .​

Answer 1

Answer:

The turning effect is the same in both the case T1 = T,

Load x Lever arm = Load x Lever length

80 N 0.25 x 10-2 = 32 Lever length Lever length (80 N x 0.25 x 10-2) / 32 Lever length = 0.625 m 62.5 cm

Explanation:

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Answer 2

Aɴsᴡᴇʀ:

32N x Force arm

= 80N x 0.25m Force arm

= 80/32 x 25/100 = 0.625m

Exᴘʟᴀɴᴀᴛɪᴏɴ:

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