A nut can be opened by a lever of length 0.25 m
applying a force of 80N. What should be the leng
of lever, if a force of 32 N is enough to open t
nut?
Anyone please tell me the answer and I will mark you the brainliest .
Answers
Answered by
11
Answer:
The turning effect is the same in both the case T1 = T,
Load x Lever arm = Load x Lever length
80 N 0.25 x 10-2 = 32 Lever length Lever length (80 N x 0.25 x 10-2) / 32 Lever length = 0.625 m 62.5 cm
Explanation:
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Answered by
30
Aɴsᴡᴇʀ:
32N x Force arm
= 80N x 0.25m Force arm
= 80/32 x 25/100 = 0.625m
Exᴘʟᴀɴᴀᴛɪᴏɴ:
Pʟs ᴍᴀʀᴋ ᴀs ʙʀᴀɪɴʟɪᴀsᴛ ᴀɴᴅ ғᴏʟʟᴏᴡ ᴍᴇ✌️
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