A nut can be opened by a lever of length 0.2m by applying a force of 20N. What should be the length of lever, if a force of 40N is enough to open the nut?
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A mechanic unscrews a nut by applying a force of 120 N on a spanner of length 40 cm. What should be the required length of the spanner in order to apply only 40 N force ? Torque (τ)=120N×40100=48Nm. In the 2nd case, applied force F = 40 N and the length of the radius vector is to be found.
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