Question

A nut can be opened by a lever of length 0.50 m by applying a force of 80N. What should bt the length of lever, if a force of 35N is enough to open the nut?​

Answer 1

diameter copper wire is mm diameter sealed end to end to a 4.00mm diameter Iron rod of 8.0 and current of 8.0 A is sent through copper wire find the current density in and current density in the copper wire

Answer 2

Answer:

Length of the lever = 1.143 m

Explanation:

To open the nut equal amount of Torque should be applied at every case

Torque when 80 Newton was applied $= 80 Newton \times 0.5 m = 80\times0.5 N.m = 40 N.m$

Torque will be same when 35 Newton force will be applied

Let the length of the lever in this case be x m

$35\times x=35x = 40\\\implies 35x = 40\\\implies x=\frac{40}{35}=\frac{8}{7}=1.143 m$