Question

A nut has been tightened by a force of 200N using 10 cm long spanner is required to loosen the same nut with 150 N force

Answer 1

Explanation:

let us use the equation

torque = r×F

so the same torque will be required to open the

nut with 150 N force since the nut is the same

torque=200×0.1=20Nm

now

20Nm=F×r

20=150×r

r=20/150=4/30=0.133m=13.3cm

Answer 2

Answer:

The length of spanner required is 13.3cm

Explanation:

Given that,

First case

Force applied to tighten nut=200N

length of spanner=10cm

Second case

Force applied to tighten nut=150N

length of spanner=?

We know that the Torque(T) is same is both cases

$T = F \times r$

Since torque is same in both cases,we have an relation

$F _{1} r_{1} = F_{2} r_{2}$

By substituting given values,we get

$200 \times 10 = 150 \times r _{2} \\ = = > r_{2} = 13.3cm$

Therefore,the length of spanner required is 13.3cm

#SPJ2