A nut has been tightened by a force of 200N using 10 cm long spanner is required to loosen the same nut with 150 N force
Answers
Answered by
8
Explanation:
let us use the equation
torque = r×F
so the same torque will be required to open the
nut with 150 N force since the nut is the same
torque=200×0.1=20Nm
now
20Nm=F×r
20=150×r
r=20/150=4/30=0.133m=13.3cm
Answered by
6
Answer:
The length of spanner required is 13.3cm
Explanation:
Given that,
First case
Force applied to tighten nut=200N
length of spanner=10cm
Second case
Force applied to tighten nut=150N
length of spanner=?
We know that the Torque(T) is same is both cases
Since torque is same in both cases,we have an relation
By substituting given values,we get
Therefore,the length of spanner required is 13.3cm
#SPJ2
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