Question

A nut is opened by wrench of length 20cm. If the least force required is 10N, find the moment of force needed to turn the nut. ​

Answer 1

${\huge{\boxed{\mathcal{\red{Answer}}}}}$

Moment of force = 2Nm

${\huge{\boxed{\mathcal{\red{Explanation}}}}}$

It is given that :-

Nut is opened by :-

Length of wrench = 20cm = 0.2m

Force applied = 10N

______________________________________

Now the moment of force is equal to the product of force applied and length of tool or object.

Therefore in this case the moment of force required to turn the nut will be :-

Length of wrench × Force applied

$moment \: of \: force \: = \: 0.2 \times 10 \\ moment \: of \: force = 2nm$

Therefore moment of force required to turn the nut is 2nm.

______________________________________

BY SCIVIBHANSHU

THANK YOU

STAY CURIOUS

Answer 2

Given :-

Force applied on the nut = 10 N

Length of wrench = 20 cm

To Find :-

The moment of force needed to turn the nut.

Analysis :-

Here we are given with the force and the distance.

In order to find the moment of force substitute the given values in the question such that momentum of force is equal to force multiplied by distance and find the force needed to turn the nut.

Solution :-

We know that,

• p = Momentum
• s = Displacement
• f = Force

Using the formula,

$\underline{\boxed{\sf Momentum=Force \times Displacement}}$

Given that,

Force (f) = 10 N

Displacement (s) = 20 cm = 0.2 m

Substituting their values,

⇒ 10 × 0.2

⇒ 2 Nm

Therefore, the moment of force needed to turn the nut is 2 Nm.