A nut is openen by a wrench of length 10cm.if the least force is 5.0N,find the moment of force needed to turn the nut
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Answered by
3
as we know that
t=f*d therefore
d=10cm=10 /100=0.1m
f=5
so,
t=5*0.1
t=0.5 Nm
Answered by
2
Hey there!
Answer:
0.5 N m
Explanation:
Given,
Length = 10 cm = 0.1 m
Force = 5.0 N
We know,
Moment of force = Length * force
= 0.1 * 5
= 0.5 N m
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