A nut which can be broken by applying a force of 40 Kgf is broken by using a nut cracker having its handle 20 cm long, by placing it at a distance 2 cm from the hinge. calculate the minimum force needed to break the nut .
(ans - 4kgf)
Answers
Answered by
9
Answer:
4 kgf is the minimum force needed to break the nut.
Explanation:
We have,
- Load = 40 kgf
- Load arm = 2 cm
- Effort arm = 20 cm
To find,
- Effort
Solution,
>> By the principle of moments,
=> Load × Load arm = Effort × Effort arm
=> 40 kgf × 2cm = Effort × 20 cm
=> Effort = (40 × 2)/20
∴ Effort = 4 kgf.
Answered by
3
Given : Load = 40kgf.
Load arm = 2 cm.
Effort arm = 20 cm.
To Find : Minimum force needed to break the nut.
Solution :
Load = 40kgf
Load arm = 2cm.
Effort arm = 20cm.
By the principle of moments,
Load × Load arm = Effort × Effort arm
40kgf × 2cm = Effort × 20 cm
Effort = (40 × 2)/20
Effort = 4kgf.
Thus, Effort of minimum force needed to break the nut is 4kgf .
Hence, Minimum force needed to break the nut is 4kgf.
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