Question

a nut which can be broken by applying a force of 40 kgf is broken by using a nht cracker having it's handle 20cm long, by placing it at a distance 2cm from the hinge.Calculate the minimum force required to break the nut.

Answer 1

20kgf minimum force

Answer 2

Concept

• In physics and mechanics, torque is the rotational equivalent of linear force.
• Also known as moment, moment of force, rotational force, or rotational effect, depending on the field of study.
• This represents the ability of the force to change the rotational movement of the body.

Given

A nut which can be broken by applying a force of 40 kgf is broken by using a nht cracker having it's handle 20cm long, by placing it at a distance 2cm from the hinge

Find

The minimum force required to break the nut.

Solution

The steps are as follow:

• F = 50 kgf L= 20 cm x= 2 cm given
• Torque will be transferred from handle to mouth of cutter
• T*L = F*x
• T*20 = 50*2
• T = 5 kgf

So the minimum force required to break the nut will be 5 kgf

#SPJ3