A object allowed to fall freely from height 20 m. After what distance its velocity becomes half of final velocity. ans:-5m how explain please...
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Explanation:
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s
2
By using the formula:
v
2
=u
2
+2as
v
2
=0
2
+2×10×20
v
2
=400
v
2
=
400
v=20m/s
For calculating time:
V=u+at
20=0+10×t
t=
10
20
t=2 sec
The the stone will hit the ground with a velocity of 20 m/s in sec.
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