Physics, asked by patelvaidik2232, 11 hours ago

A object allowed to fall freely from height 20 m. After what distance its velocity becomes half of final velocity. ans:-5m how explain please...​

Answers

Answered by Anvipawar
3

Explanation:

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s

2

By using the formula:

v

2

=u

2

+2as

v

2

=0

2

+2×10×20

v

2

=400

v

2

=

400

v=20m/s

For calculating time:

V=u+at

20=0+10×t

t=

10

20

t=2 sec

The the stone will hit the ground with a velocity of 20 m/s in sec.

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