Question

a object having a mass 2 kg and moving at 14 m/s collides with another object of mass 5 kg at rest and sticks to it . find the speed of this combination​

Answer 1

Explanation:

$\sf {m}_{1} = 2 \: kg \\ \sf {m}_{2} = 5 \: kg \\ \sf {v}_{1} = 14 \: m/s \\ \sf {v}_{2} = 0 \: m/s \\ \\ \sf Initial momentum = {m}_{1}{v}_{1} + {m}_{2}{v}_{2} \\ \\ \sf = 2 × 14 + 5 × 0 \\ \\ \sf = 28\: kg \:m/s \\ \\ \sf Final \:momentum = ( {m}_{1} + {m}_{2})v \\ \\ \sf = ( 2 + 5 )v \:kg\:m/s \\ \\ \sf = 7v \\ \\ \sf By\:the\: conservation\:of\: momentum \\ \\ \sf initial\:momentum = final\: momentum \\ \\ \sf 28 = 7v \\ \\ \sf v = \: 4 m/s \\ \\ \sf So\:the\:speed \:of\: combination\:is\:4\:m/s$

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