Question

a object of height 5 cm is place at a distance of 15 cm from a concave mirror of radius of curvature 60 cm.
find the position of image, magnification and size of the image.​

Answer 1

Answer:

Here is a proper solution to the problem:

We are given R = 20 cm. Then f = R/2 = 10 cm.

Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.

The image distance being positive means that it is REAL. Real images are INVERTED.

The magnification is (30 / 15 = 2 x). The image is MAGNIFIED, and located on the same side as the object.

Since the mag is 2 X, the height of the image (its size) is: 5 x 2 = 10 cm.

Answer 2

Explanation:

Answer:

Here is a proper solution to the problem:

We are given R = 20 cm. Then f = R/2 = 10 cm.

Use the mirror formula: 1/10 = 1/15 + 1/Di → Di = 30 cm.

The image distance being positive means that it is REAL. Real images are INVERTED.

The magnification is (30 / 15 = 2 x). The image is MAGNIFIED, and located on the same side as the object.

Since the mag is 2 X, the height of the image (its size) is: 5 x 2 = 10 cm.