A object of mass 120N on earth surface;it will become 30N.?
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Answered by
0
Hey !!!
I think ur question is incomplete and incorrect....
Cuz mass can never be in N...
It must be weight....
Re post the question
I think ur question is incomplete and incorrect....
Cuz mass can never be in N...
It must be weight....
Re post the question
Answered by
1
HEY MATE !!!
YOUR ANSWER AS FOLLOWS:-
Given Weight at Earth’s surface = W = 120 N
ApparentWeight at a height h from Earth’s surface = W’ = 30 N
W and W’ are related as
W’ = W [R / (R + h)]^2
W’ / W = [R / (R + h)]^2
30 / 120 = [R / (R + h)]^2
1/2 = R / (R + h)
R + h = 2R
h = R
∴ It’s weight will be 30 N at a height equal to radius of Earth
Regards
YOUR ANSWER AS FOLLOWS:-
Given Weight at Earth’s surface = W = 120 N
ApparentWeight at a height h from Earth’s surface = W’ = 30 N
W and W’ are related as
W’ = W [R / (R + h)]^2
W’ / W = [R / (R + h)]^2
30 / 120 = [R / (R + h)]^2
1/2 = R / (R + h)
R + h = 2R
h = R
∴ It’s weight will be 30 N at a height equal to radius of Earth
Regards
sanjay00768:
net me se hum bhi dekhe hai bhai
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