a object of mass 1kj is allowed to fall from a height of 50 m calculate the kinetic and potential energy at end of 2 seconds take g=10m/s²
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Answer:
given that,
mass m = 1kg
height h = 50m
time t = 2sec
gravity g = 10m/sec²
kinetic energy K = ?
potential energy P = ?
Explanation:
for free falling initial velocity u = 0
now procced,
from 1st equation of NLM
v = u+at
v = 0+10×2
v = 20m/sec
&from 3rd equation of NLM,
v² = u²+2as
20² = 0+ 2×10×s
400 = 20s
s = 20m
so,
K = (1/2)mv²
= (1/2)×1×20²
= 200joule answer
P = -mgh
= -1×10×20
= -200joule answer
-ve sign indicated that potential decrease
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