Question

A object of mass 5 kg is accelerated
uniformly from a velocity of 4 m/s to 8 m/s in
0.8s, when an large force is applied. The
impulse applied on the body is calculated as
From, v = utat
8 = 4 + ax 0.8
=> a = 5 m/s²
.: Force, F = ma= 5 x 5 = 25 N
• Impulse = F. At
= 25 x0.8 = 20 (N-s)
Calculate the impulse on the object by
alternate method.​

Answer 1

Answer:

20Ns

Explanation:

m=5kg

u=4m/s

v=8m/s

t=0.8s

Impulse=?

F=m(v-u)/t

F=5(8-4)/0.8

F=5(4)/0.8

F=20/0.8

F=25N

• Impulse=F×t

Impulse=25×0.8

=20Ns