Question

a object projected with a speed 20ms with 60° horizontal the horizontal speed is​

Answer 1

Answer:

The radius of curvature will be minimum at the highest point of trajectory.

Horizontal velocity at that point  vh=10cosθ=10×0.5=5 m/s

Vertical velocity at that point  vv=0

⇒mRminvh2=mg

⇒Rmin=gvh2=9.8(5)2≃2.55m

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Explanation:

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Answer 2

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