Question

A object starting from rest acquires a velocity of 25m/s in 10s .If mass of object is 3kg .Find Force applied on the object. Hint:- Find Acceleration then Use newtons second law .


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Answer 1

Answer:

The force applied on the object is 7.5 N.

Step-by-step-explanation:

We have given that,

• Initial velocity of object ( u ) = 0 m/s
• Final velocity of object ( v ) = 25 m/s
• Time ( t ) = 10 s
• Mass of object ( m ) = 3 kg

We have to find the force applied on the object.

Now, we know that,

$\displaystyle{\pink{\sf\:Acceleration\:=\:\dfrac{Change\:in\:velocity}{Time}}}$

$\displaystyle{\implies\sf\:Acceleration\:=\:\dfrac{Final\:velocity\:-\:Initial\:velocity}{Time}}$

$\displaystyle{\implies\sf\:a\:=\:\dfrac{v\:-\:u}{t}}$

$\displaystyle{\implies\sf\:a\:=\:\dfrac{25\:-\:0}{10}}$

$\displaystyle{\implies\sf\:a\:=\:\cancel{\dfrac{25}{10}}}$

$\displaystyle{\implies\boxed{\blue{\sf\:a\:=\:2.5\:m/s^2}}}$

Now, according to Newton's second law of motion,

$\displaystyle{\sf\:Force\:\propto\:Acceleration}$

$\displaystyle{\implies\sf\:F\:=\:Mass\:\times\:Acceleration}$

$\displaystyle{\implies\sf\:F\:=\:m\:a}$

$\displaystyle{\implies\sf\:F\:=\:3\:kg\:\times\:2.5\:m/s^2}$

$\displaystyle{\implies\sf\:F\:=\:7.5\:kg\:.\:m/s^2}$

$\displaystyle{\implies\sf\:F\:=\:7.5\:N}$

$\displaystyle{\therefore\:\underline{\boxed{\red{\sf\:Force\:=\:7.5\:N}}}}$

∴ The force applied on the object is 7.5 N.

Answer 2

Answer:

• hope the above image helps..refer with that..