Question

a object when throwed from a height reaches a distance of 24.5m in the last second. Find the height from which it was throwed. Please answer as soon as possible. I will give branliest. It is very urgent

Answer 1

Given,

last sec t= 1

displacement s= 24.5

we have,

s=u*t+(1/2)(a*t^2)

Here, the object is thrown from a height

u= 0

a= g= 9.8 m/s^2

s=1/2(9.8*t^2)

=> s=4.9 t^2

Distance travelled by the object in the last sec is 24.5

4.9 t^2 - 4.9(t-1)^2= 24.5

t^2 - (t-1)^2 = 5

(t-t+1)(t+t-1)= 5

(2t-1)= 5

2t= 6

t= 3

now,

s=u*t=(1/2)(a*t^2)

s= 0+(1/2)*9.8*9

s= 44.1 m

So the height from which ball was thrown= 44.1 m

;)

hope it helps