A object which has a mass of 70k.g is Moving at the Velocity of 30k.m/h.A force Was used to stop the object that took 30 seconds to stop.How much Force was applied?
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Answered by
0
Answer:
19.4 N
Explanation:
Force = m*a = m*(v-u/t). (u= 30*5/18 = 25/3 m/sex)
= 70* (25/3*30) = 7*25/9 = 175/9= 19.44 N
Answered by
0
Answer:
19.44 N please mark this the brainliest!!!and i hope this answer helps you!
Explanation:
v=u +at (v=30 km/hr=25/3 m/sec)
0=25/3 -a*30
30a=25/3
a=25/90 m/sec²
hence the force used was=m*a=70*25/90=175/9 N=19.44N
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