Question

a object with a mass 10kg moves at constant velocity of 10m/s. A constant force then acts for 4 seconds on a the object and gives it a speed of 2m/s in opposite direction. what is the acceleration produced?

Answer 1

We know that acceleration = final velocity - initial velocity /time
that is, (v - u)/t

Here u = 10m/s
v = -2m/s (We have taken v as negative because it moves in opposite direction)

So acceleration a = (v - u)/t

=> a = [-2 - 10)]/4

=> a = (-12)/4

=> a = -3m/s²

Since, the body starts moving in opposite direction, the acceleration is negative.

Hence, your answer is -3m/s²

Hope it helps dear friend ☺️✌️

Answer 2

hey buddy !! here's your answer...

★ according to Newton's second law ,

F= dp/dt

ma = m (v-u)/t

★ cancelling m from both sides ,

a = (v-u)/t

a = (2+10)/4 ...( taking initial direction negative )

a = 12 /4

a = 3 m/s²✔️✔️

hope it helps !!❤️✌️

bonne journée !! ⭐⭐