a object with a mass 10kg moves at constant velocity of 10m/s. A constant force then acts for 4 seconds on a the object and gives it a speed of 2m/s in opposite direction. what is the acceleration produced?
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Answered by
37
We know that acceleration = final velocity - initial velocity /time
that is, (v - u)/t
Here u = 10m/s
v = -2m/s (We have taken v as negative because it moves in opposite direction)
So acceleration a = (v - u)/t
=> a = [-2 - 10)]/4
=> a = (-12)/4
=> a = -3m/s²
Since, the body starts moving in opposite direction, the acceleration is negative.
Hence, your answer is -3m/s²
Hope it helps dear friend ☺️✌️
that is, (v - u)/t
Here u = 10m/s
v = -2m/s (We have taken v as negative because it moves in opposite direction)
So acceleration a = (v - u)/t
=> a = [-2 - 10)]/4
=> a = (-12)/4
=> a = -3m/s²
Since, the body starts moving in opposite direction, the acceleration is negative.
Hence, your answer is -3m/s²
Hope it helps dear friend ☺️✌️
cherry14327:
when v=2 and u=10 why did u substitute v in place of u and u in place of v?
both results will be same
see u = 10 v = -2 => -2 - 10/4 => -12/4 = -3m/s² as i said
Answered by
20
hey buddy !! here's your answer...
★ according to Newton's second law ,
F= dp/dt
ma = m (v-u)/t
★ cancelling m from both sides ,
a = (v-u)/t
a = (2+10)/4 ...( taking initial direction negative )
a = 12 /4
a = 3 m/s²✔️✔️
hope it helps !!❤️✌️
bonne journée !! ⭐⭐
★ according to Newton's second law ,
F= dp/dt
ma = m (v-u)/t
★ cancelling m from both sides ,
a = (v-u)/t
a = (2+10)/4 ...( taking initial direction negative )
a = 12 /4
a = 3 m/s²✔️✔️
hope it helps !!❤️✌️
bonne journée !! ⭐⭐
hi
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