A object with the mass 5kg moves at a constant velocity of 8m/s .A constant force then acts for 6 second on the object giving its a speed of 4m/s in opposite.The acceleration produced is?
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Answer:
a = m(v-u/t)
a = 5(8-4/6)
a = 5(4/6)
a = 5(2/3)
a = 10/3
The acceleration produced is 10/3 m/s²
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