Question

A objects is thrown vertically up with a speed of 50 m/s. find the maximun hight obtained by the objects?

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Answer 1

Answer:

ANSWER

(a) Initial velocity of ball (u)=50m/s, acceleration of ball =−g,

final velocity at the highest point (v)=0

So applying the 3rd equation of motion we get:

Answer 2

Answer:

ANSWER

Initial velocity, u=50ms

−1

At maximum height final velocity, v=0

Apply first kinematic equation of motion

v=u+at

0=50−10t

t=5sec

Apply second kinematic equation of motion

v

2

−u

2

=2as

0

2

−50

2

=2(−10)h

h=125m

Hence, at maximum height final velocity is zero, time taken 5secand maximum height is 125m