a) Obtain the equation for scape velocity.
b) Find the escape velocity of a plane whose mass is same as that of the earth and radius 4 times.
(escape velocity of earth is 11.2 km/sec)
Answers
Answer:
b) number Ka answer hai
Explanation:
Escape Velocity Formula
You must have seen rockets leaving the earth to go into space. Then you must have also noticed they require a very huge kick-start in order to leave the surface of the earth. It is because of the strong gravitational field of the surface of the earth. Thus, this is where escape velocity comes in. In this article, you will learn about the escape velocity formula and see how the formula can be used to find out the escape velocity of any object or body.
Definition
Escape Velocity is referred to as the minimum velocity needed by anybody or object to be projected to overcome the gravitational pull of the planet earth. In other words, the minimum velocity that one requires to escape the gravitational field is escape velocity.
Basically, it means escaping the land without any chance of falling back. Therefore, any object or body having escape velocity on the surface of the earth can totally escape the gravitational field of the earth in addition to avoiding the losses due to the atmosphere.
For instance, if you see that a spacecraft leaves the earth’s surface it requires a speed of 7 miles per second or about 25,000 miles per hour to leave the earth without ever falling back to the surface of the earth.
Escape Velocity Formula
Escape velocity refers to the minimum velocity which is needed to leave a planet or moon. For instance, for any rocket or some other object to leave a planet, it has to overcome the pull of gravity.
The formula for escape velocity comprises of a constant, G, which we refer to as the universal gravitational constant. The value of it is = 6.673 × 10-11 N . m2 / kg2. The unit for escape velocity is meters per second (m/s).