Question

A of 3 please solve and take 20 points ​

Answer 1

${ \underbrace{\underline{ \large{ \sf{Understanding \: the \: Question}}}}}$

Here in this question we have given a figure and we have to find area of the figure. We can notice that the given figure is made up of 2 trapeziums with identical sides and altitudes. So we can find the area of figure by adding area of both trapeziums.

So let's start!

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~Area of trapezium FCDE

⇝ Area of trapezium=½×(Sum of || Sides)×height

⇝ Area of trapezium=½×(15cm+20cm)×10cm

⇝ Area of trapezium=½×25cm×10cm

⇝ Area of trapezium=25cm×5cm

⇝ Ar.of trapezium FCDE=125cm²

Ar.of trapezium FCDE=125cm²

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~Area of trapezium ABCF

⇝ Area of trapezium=½×(Sum of || Sides)×height

⇝Area of trapezium=½×(25cm)×12cm

⇝ Area of trapezium=25cm×6cm

⇝ Area of trapezium=25cm×6cm

⇝ Area of trapezium=150cm²

Ar.of trapezium ABCF=150cm²

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~Area of figure ABCDEG

⇝ Ar.ABCDEF=Ar.FCDE + Ar.ABCF

⇝ Ar.ABCDEF=125cm² + 150cm²

⇝ Ar.ABCDEF=275cm²

Hence the required area of figure is 275cm².

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ADDITIONAL INFORMATION:

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

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Answer 2

Answer:

To the nineteenth-century historian the French Revolution was largely a battle of ideas and its outbreak the more or less fortuitous climax to a series of political crises—the rejection of Calonne's proposals for tax reform by the Assembly of Notables of 1787, the convocation of the Estates General, and the king's ...