Question

A of conductor A of resistance R is stretched to double its length and another conductor B of resistance 2R is cut in two equal lengths. The ratio of the resistances of the stretched conductors A' and 'half part of the conductor B.

1) 2:1
2) 1:1
3) 4:1
4) 8:1​

Answer 1

Answer:

8:1

Explanation:

Resistance of half part=

R=pL/A

L=L/2

A=A

because he didnt change the area.

R=pL/2/A

R=1/2 pL/A--------(1)

Resistance of the doubled length wire=

R=pL/A

L=2L

A=A/2

so,R=p*2L/A/2

     =4pL/A------(2)

Ratio=

if u divide (2) by (1), u will get the ratio.

If u do the calculation, u will get 8:1.

IF U WANT MORE ANSWERS,

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

.

DONT ASK ME..