Question

a of mass 500 gram moving at 50 M per second strikes a nail nail stops the hammer in very short time of 0.01 seconds what is the force of the nail on the hammer

Answer 1

Given , mass of hammer

(m) = 500g = 0.5kg

Initial velocity of hammer

(u) = 50 m/s

Final velocity of hammer

(v) = 0 m/s

Duration (t) = 0.01 s

Using second law of motion ,

F = ma = m (v-u) / t 

⇒  F = 0.5 ( 0 - 50 ) / 0.01 

= (0.5 × - 50 ) / 0.01 

= - 2,500 N 

The - ve sign shows the force of 2500 N acts in the opposite direction of motion .