a of mass 500 gram moving at 50 M per second strikes a nail nail stops the hammer in very short time of 0.01 seconds what is the force of the nail on the hammer
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Given , mass of hammer
(m) = 500g = 0.5kg
Initial velocity of hammer
(u) = 50 m/s
Final velocity of hammer
(v) = 0 m/s
Duration (t) = 0.01 s
Using second law of motion ,
F = ma = m (v-u) / t
⇒ F = 0.5 ( 0 - 50 ) / 0.01
= (0.5 × - 50 ) / 0.01
= - 2,500 N
The - ve sign shows the force of 2500 N acts in the opposite direction of motion .
(m) = 500g = 0.5kg
Initial velocity of hammer
(u) = 50 m/s
Final velocity of hammer
(v) = 0 m/s
Duration (t) = 0.01 s
Using second law of motion ,
F = ma = m (v-u) / t
⇒ F = 0.5 ( 0 - 50 ) / 0.01
= (0.5 × - 50 ) / 0.01
= - 2,500 N
The - ve sign shows the force of 2500 N acts in the opposite direction of motion .
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