Question

a oick up truck is moving at 25 m/s At the bottom of a hill. four seconds later it reaches the top of the hill moving at 10m/s. whats was the acceleration of the rider? plsss answer it correctly thankyou​

Answer 1

Question:-

• A pick up truck is moving at 25 m/s At the bottom of a hill. Three seconds later it reaches the top of the hill moving at 10m/s. whats was the acceleration of the rider?

To Find:-

• Find the acceleration.

Solution:-

Here ,

• u = initial velocity

• v = final velocity

• a = acceleration

• s = distance

• t = time

Now ,

We have to find the acceleration:-

$\sf\longrightarrow \: v = u + at$

$\sf\longrightarrow \: 10 = 25 + 3a$

$\sf\longrightarrow \: 3a = 10 - 25$

$\sf\longrightarrow \: 3a = - 15$

$\sf\longrightarrow \: a = \cancel\dfrac { - 15 } { 3 }$

$\sf\longrightarrow \: a = - 5 \: { m/s }^{ 2 }$

Hence ,

• Acceleration is - 5m/s²