Question

(a)
ok
A boy walks to his school at a distance of 6 km with constant
speed of 2.5 km/h and walks back with a constant speed of
4kmh. His average speed for round trip expressed in km/h,is

(a)24/13
(b)40/13
(C) 3
(d)1/2
​

Answer 1

Answer:

option (b)

Explanation:

Time for forward journey t1=2.56=512=2.4 hr

Time for backward journey t2 = 46 = 1.5 hr

Average speed =2.4+1.56+6=3.912=1340 km/hr

hope it help

Answer 2

(b) 40/13

Here we use simple SDT Formula...

Hope u can get it...