Chemistry, asked by kaushickeshri9576, 1 month ago

(a) On treatment of (S)-2-iodo octane with Nal in solution its optical activity is lost. Explain.

Answers

Answered by jasintashah
0

Answer:

Sorry

Explanation:

Idont know this answer

Answered by nsgiri2650
0

Explanation:

Optically active 2-iodibutane on treatment with NaI in acetone undergoes racemisation.

Repeated Walden inversions on the reactant and its product eventually gives a racemic mixture.

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